FedEx FX1740 Flight Status from Indianapolis to Allentown, United States today

Domestic flight FedEx FX1740 from Indianapolis (IND) United States to Allentown (ABE) United States operated by FedEx Express. Scheduled time of departure from Indianapolis International Airport is 04:42 America/Indiana/Indianapolis and scheduled time of arrival in Lehigh Valley International Airport is 05:56 America/New_York. The duration of the flight is 1 hours 14 minutes.

FX1740 - FDX1740 FedEx Express (FX)
IND Indianapolis United States
Flight IND to ABE
ABE Allentown United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 04:42
Arrival Lehigh Valley International Airport
IATA: ABEICAO: KABE
Scheduled 05:56
FX1740 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 14 minutes
  • Flight Distance: 930 kms / 578 miles
Airline
  • FedEx Express
  • IATA: FX
  • ICAO: FDX
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A300-600 Freighter
  • Callsign: F-KIND5
  • Departure Timezone: America/Indiana/Indianapolis
  • Arrival Timezone: America/New_York
  • Current Time in Indianapolis: Thursday 2024-03-28 15:27 PM
  • Current Time in Allentown: Thursday 2024-03-28 15:27 PM

Frequently asked questions, answered

How long is the flight from Indianapolis to Allentown?

On average, nonstop flight takes 1 hour(s) 14 minutes, with the flight distance of 930 km (578 miles).

What type of aircraft is used for the FedEx FX1740 flight?

All FedEx FX1740 flights are operated using Airbus A300-600 Freighter aircraft.